EXAMPLE 3: THE WORK-ENERGY RELATION


 

 

 

A particle moves under the constant horizontal force and gravity from point A to B on the smooth circular bar. Calculate the work of the forces applied on the particle.

 


Solution:

        Work of N: N is perpendicular to the path at all times and, as a result, has no component tangent to the path . Therefore, N does no work from A to B.

        Work of and mg: